(x+4)(2x^2-7x-4)=0

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Solution for (x+4)(2x^2-7x-4)=0 equation: 


Simplifying
(x + 4)(2x2 + -7x + -4) = 0

Reorder the terms:
(4 + x)(2x2 + -7x + -4) = 0

Reorder the terms:
(4 + x)(-4 + -7x + 2x2) = 0

Multiply (4 + x) * (-4 + -7x + 2x2)
(4(-4 + -7x + 2x2) + x(-4 + -7x + 2x2)) = 0
((-4 * 4 + -7x * 4 + 2x2 * 4) + x(-4 + -7x + 2x2)) = 0
((-16 + -28x + 8x2) + x(-4 + -7x + 2x2)) = 0
(-16 + -28x + 8x2 + (-4 * x + -7x * x + 2x2 * x)) = 0
(-16 + -28x + 8x2 + (-4x + -7x2 + 2x3)) = 0

Reorder the terms:
(-16 + -28x + -4x + 8x2 + -7x2 + 2x3) = 0

Combine like terms: -28x + -4x = -32x
(-16 + -32x + 8x2 + -7x2 + 2x3) = 0

Combine like terms: 8x2 + -7x2 = 1x2
(-16 + -32x + 1x2 + 2x3) = 0

Solving
-16 + -32x + 1x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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